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maka pusat ( - x , y ) dengan r = x = y
pusat berada pd 2x - 3y - 5 = 0
2x - 3 (- x) - 5 = 0
2x + 3x - 5 = 0
5x - 5 = 0
5x = 5
x = 5/5
x = 1
pusat ( - 1 , 1) dan r = 1
pers lingkaran
(x - a)² + (y - b)² = r²
(x - (-1))² + (y - 1)² = 1²
(x + 1)² + (y - 1)² = 1²
x² + 2x + 1 + y² - 2y + 1 = 1
x² + y² + 2x - 2y + 2 = 1
x² + y² + 2x - 2y + 2 - 1 = 0
x² + y² + 2x -2y + 1 = 0
jawaban : A