" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
1][
Persamaan posisi
r = 4i + 3j
Besar vektor r
|r| = √(rx² + ry²)
= √(4² + 3²)
= 5 m ← jwb
Gambar
2][
rP= 5 i + 7j
rQ = 11 i + 15 j)
Perpindahan
r = rQ - rP
= 11 i + 15 j - (5 i + 7 j)
= 6 i + 8 j ← jwb
Besar perpindahan
|r| = √(rx² + ry²)
= √(6² + 8²)
= 10 m ← jwb
Arah perpindahan
tan α = ry / rx
tan α = 8/6
α = 53° ← jwb
3][
Persamaan posisi
r(t) = 4t i + (2t - 3t²) j
Posisi saat t = 2 s
r(2) = 4 · (2) i + (2 · (2) - 3 · (2)²) j
= 8 i + (4 - 12) j
= (8 i - 8 j) m ← jwb
Posisi saat t = 4 s
r(4) = 4 · (4) i + (2 · (4) - 3 · (4)²) j
= 16 i + (8 - 48) j
= (16 i - 40 j) m
Kecepatan rata-rata antara t = 2 s hingga t = 4 s
_ Δr (16 i - 40 j) - (8 i - 8 j)
v = ---- = -----------------------------
Δt 4 - 2
_ Δr 8 i - 32 j
v = ---- = ------------
Δt 2
_
v = (4 i - 16 j) m
Besar kecepatan rata-rata
_ _ _
|v| = √vx² + vy²)
= √(4² + 16²)
= √(4² + 4² · 4²)
= √(4² (1 + 4²)
= 4√17 m/s ← jwb