Question

Tolong dibantu jawab ya..
terimah kasih...

Answer 1

1.
Mol as =m. V
=0,1.500
=50
Mol bs konj=m. V
=0,1.500
=50

[H+] =ka. Mol as/ Mol bs konju
=10^-4. 50/50
=10^-4.1
=10^-4

pH=-log [H+]
= - log 10^-4
=4

3
Mol as =m. V
=0,1.300
30
Mol bs konju =m.v
=0,1.200
=20

[H+]=ka. Mol as/ Mol bs konju
=10^-4. 30/20
=10^-4. 1,5
=1,5. 10^-4

pH= - log [H+]
=log 1,5.10^-4
=4- log 1,5

2
Masih belum tau caranya