Question

Mohon di bantu ya teman-teman​

Answer 1

1. 10x²-9x-9 ≥ 0

x² - 9x/10 - 9/10 ≥ 0 <= lakukan kuadrat sempurna

x²- 9x/10 + (9/20)² - (9/20)² - 9/10 ≥ 0

(x - 9/20)² - 81/400 - 9/10 ≥ 0

(x - 9/20)² - 81/400 - 360/400 ≥ 0

(x - 9/20)² - 441/400 ≥ 0

( [x - 9/20] - 21/20)( [x - 9/20] + 21/20) ≥ 0

(x - 30/20)(x + 12/20) ≥ 0

(x - 3/2)(x + 3/5) ≥ 0

x ≤ -3/5 atau x ≥ 3/2

2. |5-3y| < 13

-13 < 5 - 3y < 13

-18 < -3y < 8

6 > y > -8/3

y < 6 atau y > -8/3

-8/3 < y < 6