Question

Mohon di bantu ya teman-teman​

Answer 1

Persamaan Garis kedua

(y - y₁)/(y₂- y₁) = (x-x₁)/(x₂- x₁)

(y - 1)/(13- 1) = (x-2)/(4- 2)

(y-1)/12 = (x-2)/2

y - 1 = 6x - 12

y = 6x - 11

m₁ = 6

Persamaan Garis pertama

(y - 1)/(2- 1) = (x-k)/(2- k)

y - 1= (x-k)/(2-k)

y-1= x/(2-k) - k/(2-k)

y = x/(2-k) - k/(2-k) + 1

m₂ = 1/(2-k)

Karena tegak lurus

m₁. m₂ = -1

6. 1/(2-k) = -1

6 = -2+k

k = 2+6 = 8

Answer 2

m1 = (1-13)/(2-4)

     = -12/-2

m1  = 6

m1.m2 = -1

6m2 = -1

m2 = -1/6

(2-1)/(2-k) = -1/6

1/(2-k) = -1/6

6 = -(2-k)

k-2 = 6

k = 8