Question

Mohon bantuanya dong kakak-kakak yang baik hati.

Answer 1

Verified answer

Q₁ = - 9 μC = -9×10⁻⁶ C
Q₂ = - 4 μC = -4×10⁻⁶ C
Q₃ = 5 μC = 5×10⁻⁶ C
r = 0,25 m
F₃ = __?

F₃₁ = k Q₁ Q₃ / r²
F₃₂ = k Q₂ Q₃ / r²

F₃ = F₃₁ - F₃₂
F₃ = k Q₃ • (Q₁ - Q₂) / r²
F₃ = 9×10⁹ • 5×10⁻⁶ (9×10⁻⁶ - 4 μC = 4×10⁻⁶) /( ¼)²
F₃ = 18/5 ≈ 3,6 N ✓
menuju Q₁