Penjelasan dengan langkah-langkah:
1] 1/3 . p² = 12/25
dikali 3
p² = 36/25
p = √(36/25)
p = +- 6/5
p1 = 6/5 atau p2 = -6/5
HP = { -6/5, 6/5 }
2] (y + 1)² - 9 = 0
(y + 1)² = 9
y + 1 = +- √9
y = -1 +- 3
y1 = -1 + 3
y1 = 2
y2 = -1 - 3
y2 = -4
HP = { -4, 2 }
Kode Kategorisasi : 9.2.9
Kelas 9
Pelajaran 2 - Matematika
Bab 9 - Persamaan Kuadrat
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Penjelasan dengan langkah-langkah:
1] 1/3 . p² = 12/25
dikali 3
p² = 36/25
p = √(36/25)
p = +- 6/5
p1 = 6/5 atau p2 = -6/5
HP = { -6/5, 6/5 }
2] (y + 1)² - 9 = 0
(y + 1)² = 9
y + 1 = +- √9
y = -1 +- 3
y1 = -1 + 3
y1 = 2
y2 = -1 - 3
y2 = -4
HP = { -4, 2 }
Kode Kategorisasi : 9.2.9
Kelas 9
Pelajaran 2 - Matematika
Bab 9 - Persamaan Kuadrat