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y = (2x+1)/(x-3)
y(x+3) = 2x+1
x.y+3y = 2x+1
x.y-2x = 3y+1
x(y-2) = 3y+1
x = (3y+1)/(y-2)
f⁻¹(x) = (3x+1)/(x-2)
f⁻¹(x-2) = (3(x-2)+1)/((x-2)-2)
f⁻¹(x-2) = (3x-6+1)/(x-2-2)
f⁻¹(x-2) = (3x-5)/(x-4)