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= 16² + 12²
AC = √400
AC = 20 cm
Perhatikan ΔPCT
PC = 1/2 AC
= 1/2 x 20
= 10 cm
TC² = TP² + PC²
= 24² + 10²
TC = √676
= 26 cm
Panjang kawat yang dibutuhkna = 2AB + 2BC + 4TC
= 2 x 16 + 2 x 12 + 4 x 26
= 32 + 24 + 104
= 160 cm
Jawab: A