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y = -x-b
titik potong keduanya
x²+3x+1 = -x-b
x²+3x+1+x+b = 0
x²+4x+1+b = 0
a=1, b=4, c= 1+b
syarat 1 titik potong, artinya nilai deskriminan D = 0
D = b²-4ac
0 = 4²-4(1)(1+b)
0 = 16-4-4b
4b = 12
b = 3