Question

Mohon bantuannya nomer 6 a smpai e
Pakai cara penyelesaiannya

Answer 1

Bagian a
x² -2 = 0
a = 1 , b = 0 , c = -2
maka :
x₁,x₂ = [-(0) + √{(0)² - 4(1)(-2)}  ] / 2(1)
x₁,x₂ = [ + √{8} ] / 2
x₁,x₂ = [ + 2√2 ] /2
x₁,x₂ = + √2

bagian b
x² + 3x - 1 = 0
a = 1 , b = 3 , c = -1
x₁,x₂ = [ -(3) + √{(3)² - 4(1)(-1)} ] / 2(1)
x₁,x₂ = [ -3 + √13 ] / 2

bagian c
x² + 2x - 3 = 0
a = 1 , b = 2 , c = -3
x₁,x₂ = [ -(2) + √{(2)² - 4(1)(-3)} ] / 2(1)
x₁,x₂ = [ -2 + √16 ] / 2
x₁,x₂ = [ -2 + 4 ] / 2
x₁ = 1
x₂ = -3

bagian d
2x² - x - 1 = 0
a = 2 , b = -1 c = -1
x₁,x₂ = [ -(-1) + √{(-1)² - 4(2)(-1)} ] / 2(2)
x₁,x₂ = [ 1 + √9 ] / 4
x₁,x₂ = [ 1 + 3 ] / 4
x₁ = 1
x₂ = - 1/2

bagian e
2x² + 5x - 3 = 0
a = 2 , b = 5 , c = -3
x₁,x₂ = [ -(5) + √{(5)² - 4(2)(-3)} ] / 2(2)
x₁,x₂ = [ -5 + √49 ] / 4
x₁,x₂ = [ -5 + 7 ] / 4
x₁ = 1/2
x₂ = - 3