Question

Mohon bantuannya,
Integral (cos 2x - sin 2x)^2 dx
berapa ya?

Answer 1

∫(cos(2x) - sin(2x))^2 dx

= ∫cos^2(2x) + sin^2(2x) - 2sin(2x)cos(2x) dx
= ∫1 - sin(4x) dx
= x + (1/4)cos(4x) + C