integral
∫x²(x + 3) dx [3 1] + ∫x²(x + 3) dx [5 3]
= ∫x²(x + 3) dx [5 1]
= ∫(x³ + 3x²) dx
= 1/4 x⁴ + x³
= 1/4 (5⁴ - 1⁴) + (5³ - 1)
= 1/4 (625 - 1) + 125 - 1
= 156 + 124
= 280
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INTEGRAL TENTU
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integral
∫x²(x + 3) dx [3 1] + ∫x²(x + 3) dx [5 3]
= ∫x²(x + 3) dx [5 1]
= ∫(x³ + 3x²) dx
= 1/4 x⁴ + x³
= 1/4 (5⁴ - 1⁴) + (5³ - 1)
= 1/4 (625 - 1) + 125 - 1
= 156 + 124
= 280
Verified answer
Penjelasan dengan langkah-langkah:
INTEGRAL TENTU
#AdaDigambar
#semogamembantu