Question

Mohon bantuannya....​

Answer 1

Penjelasan dengan langkah-langkah:

[tex]\int \frac{ - 16 - {6x}^{4} }{ {x}^{2} }dx \\ = \int \frac{ - 16}{ {x}^{2} } - \frac{ {6x}^{4} }{ {x}^{2} } dx \\ = \int \frac{ - 16}{ {x}^{2} } dx \: - \int \: {6x}^{2} \: dx \\ = - 16\int \frac{1}{ {x}^{2} } \: dx - \frac{ {6x}^{2 + 1} }{2 + 1} \\ = - 16( \frac{ - 1}{ {x}^{} } ) - \frac{ {6x}^{3} }{3} \\ = \frac{16}{x} - {2x}^{3} + C[/tex]

Answer 2

Penjelasan dengan langkah-langkah:

[tex] = - \frac{16}{ {x}^{2} } - \frac{6 {x}^{4} }{ {x}^{2} } dx \\ [/tex]

[tex] = - 16 {x}^{ - 2} - 6 {x}^{2} dx\\ = \frac{ - 16 {x}^{ - 1} }{ - 1} - \frac{6 {x}^{3} }{3} [/tex] + c

[tex] = \frac{16}{x} - 2 {x}^{3} + c[/tex]