Question

Mohon bantuannya 2 nomor ini. trims.

Answer 1

Biaya per hari = 40x + 1000/x - 50
B(x) = 40x + 1000x^-1 - 50
B'(x) = 40 - 1000x^-2 = 0
=> 40 = 1000/x^2
=> 40x^2 = 1000
=> x^2 = 25
=> x = 5
B(x) = 40x + 1000/x - 50
B(5) = 40(5) + 1000/5 - 50 = 200 + 200 - 50 = 350 juta
Jadi biaya minimum per hari = Rp350.000.000,00