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Mapel : Kimia
Kategori : Bab 6 Stoikiometri
Kata Kunci : Molalitas
Penyelsaian
Rumus
m = gr / Mr x 1000 / p
massa = massa jenis . volume
Massa Larutan = 1,2 . 500 = 600 gram
Massa H2SO4 = 5/100.600 = 30 gram
H2SO4, Mr = 2 + 32 + 64 = 98
Massa Air = 600 - 30 = 570 gram
m = 30 / 98 x 1000/570
= 0,537 molal