Question

Larutan asam klorida 18,25% mempunyai massa jenis 1,1 g/mL. tentukan fraksi mol masing-masing zat dalam larutan tersebut?

Answer 1

HCl = 18,25%
Air = 81,75 %

->
HCl = 18,25 gram
Air = 81,75 gram
mol HCl = 18,25/36,5 = 0,5 mol
mol air = 81,75/18 = 4,5 mol

Xt=nHcl/[nHcl+nair]
Xt=0.5/[0.5+4.5]=0.1

Fraksi mol air=1-0.1=0.9