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|x+1| = x+5 (-x)
|x+1| - x = 5
Separamos por casos
1) x + 1 - x = 5 ( si x>0)
1 = 5 (Se indefine)
2) -(x+1) - x = 5 (si x<0)
- x - 1 - x = 5
-2x - 1 = 5
-2x = 6
x = - 3