Mau poin 30 jawab soal aku dong?? Suatu parabola y = ax² + bx - c melalui titik ( 0, 4 ) , ( 1, 3 ) dan ( -2 , 12 ) tentukan : a. Nilai a, b , dam c b. persamaan parabola c. nilai y untuk x = 3
ekamiawwy = ax² + bx - c (0,4) -- > 0a+0b-c = 4 --> c = -4 (1,3) --> a+b-c = 3 --> a+b-(-4) = 3 --> a+b = -1 ....(i) (-2,12) --> 4a-2b-c = 12 --> 4a-2b+4 = 12 --> 4a-2b = 8 ....(ii) eliminasi (i) dan (ii) a+b = -1 (x2) --> 2a+2b = -2 4a-2b = 8 (x1) --> 4a-2b = 8 + 6a = 6 --> a=1 substitusi a=1 ke (i) 1+b = -1 b = -1-1 b = -2 jadi nilai a=1, b= -2 dan c = -4
(0,4) -- > 0a+0b-c = 4 --> c = -4
(1,3) --> a+b-c = 3 --> a+b-(-4) = 3 --> a+b = -1 ....(i)
(-2,12) --> 4a-2b-c = 12 --> 4a-2b+4 = 12 --> 4a-2b = 8 ....(ii)
eliminasi (i) dan (ii)
a+b = -1 (x2) --> 2a+2b = -2
4a-2b = 8 (x1) --> 4a-2b = 8 +
6a = 6 --> a=1
substitusi a=1 ke (i)
1+b = -1
b = -1-1
b = -2
jadi nilai a=1, b= -2 dan c = -4
persamaan parabola y = x² - 2x - 4
utk x=3 --> y = 9-6-4 = -1
semoga membantu ya.. :)