Matematyka z plusem 2 , zadanie 3 strona 21 podpunkty c,d :
c) (2 × 10²)³ =
2000⁵ =
d) (2:10)⁴ =
0,02⁶ =
c) 8 x 1000000 = 8 000000
d) 16 : 100000 = 0,0016
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c) 8 x 1000000 = 8 000000
d) 16 : 100000 = 0,0016