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f(1) = P 2 log (1 + 1)
3 = P . 2 log 2
3 = P
jadi nilai P = 3
jika f(3 ) maka
f(x)= P. 2 log (x +1)
= 3 . 2 log (3 + 1 )
= 3 . 2 log 4
= 3 . 2
= 6