MATEMATIKA KELAS 11-12 BANTU KAK
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29) y= x³ -27x + 6
titk balik maksimum y' = 0 dan y" <0
y' = 0
3x² -27 = 0
x² = 9
x = 3 atau x = - 3
y" = 6x --> x = - 3 --> y" = - 18 < 0
titk maks untuk x = - 3 danb y = x³ -27x + 6
y = (-3)³ -27(-3) + 6
y = 60
tik bal mak = (-3, 60)
30 ∫ (2 - x)² dx = ∫ (4 - 4x + x²) dx
= 4x - 2x² + 1/3 x³ + c
29. b. 60
30. c.
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