Masa cząsteczkowa dwutlenku pewnego metalu wynosi 87u. Tlenek ma skład typu AB2.Jaki to metal?
M= 87u
AB₂= 87u
O₂= 16u x 2 = 32u
87u - 32u = 55u
mangan
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M= 87u
AB₂= 87u
O₂= 16u x 2 = 32u
87u - 32u = 55u
mangan