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mol N = 0,25 x 0,05 = 0,0125 mol
POH = - log Kb + log
5,5 = - log + log
5,5 = 5 + log
0,5 = log
log = log
=
mol
mol = 0,00395 mol
volume = 0,00395 x 22,4 x 1000 = 88,48 ml = 88,5 ml
no.7) mol CH3COOH = 0,1 x 0 4 = 0,04 mol
NaOH + CH3COOH -----> CH3COONa + H2o
mol NaOH = x 0,04
= 0,04 mol
[NaOH] =
= 0,4 M