Question

8 dan 9.. please.. jangan komentar jika tak menjawab

Answer 1

8. pH = 9 ⇒ pOH = 5 ; OH^- = 10^-5
   OH^- = √ Kb × ( gr ÷ Mr) × (1000 ÷ mL)
   10^-5 = √ 10^-5 × (gr ÷ 53,5) × (1000 ÷ 200)
   10^-10 = 5 × 10^-5 × (gr ÷ 53,5)
   gr = (10^-10 × 53,5) ÷ 5 × 10^-5
       = 1,07

9. pH = 2 ; H^+ = 10^-2
     H^+ = a × M HCl
     10^-2 = 1 × M HCl
     M HCl = 10^-2

     NH4OH + HCl ⇒ NH4Cl
m    40          10
b      10          10        10
s      30            -        10

OH^- = Kb × (mol basa ÷ mol garam)
       = 10^-5 × (40 ÷ 10)
       = 4 × 10^-5
pOH = 5 × log 4
pH = 9 + log 4 ≈ 9 + 2 log 2

Answer 2

8.a
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