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(2) 1 dwasa + 3 ank" = 130,000 | x2 | = 2 dwasa+6 ank" = 260,000
(metode eliminasi )
= -4 ank" = -120,000
= ank" = -120,000/-4
= ank" = 30,000
substitusikan ank" = 30,000 ke pers.(2)
1 dwasa + 3 ank" = 260,000
= 1 dwasa+ 3 (30,000) = 260,000
=1 dwasa+90,000= 260,000
=1 dwasa = 260,000-90,000
= 1 dwasa = 170,000
jadi, 3 dwasa + 5 ank"
3 (170,000)+5(30,000)
510,000+150,000
660,000
a= anak anak
2d+2a=140.000 | x1| 2d+2a=140.000
1d+3a=130.000 | x2| 2d+6a=260.000
____________ _
-4a=-120.000
a=30.000
2d+2a=140.000
2d+2(30.000)=140.000
2d+60.000=140.000
2d=80.000
d=80.000 : 2
d= 40.000
jadi, tiket untuk 3 orang dewasa dan 5 anak anak :
3d+5a
=3(40.000)+ 5 (30.000)
=120.000 +150.000
=270.000