mając dany trójkąt równoboczny o boku 8 cm. Oblicz:
a) h
b) P
c) R
Oblicz pole sześciokąta foremnego o boku 5
1.a)
h=
h==4√3(cm)
b)
P=
P=16√3(cm²)
c)
2.
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1.a)
h=![\frac{a\sqrt{3}}{2} \frac{a\sqrt{3}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5Csqrt%7B3%7D%7D%7B2%7D)
h=
=4√3(cm)
b)
P=![\frac{a^{2\sqrt{3}}}{4} \frac{a^{2\sqrt{3}}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%5Csqrt%7B3%7D%7D%7D%7B4%7D)
P=![\frac{8^{2\sqrt{3}}}{4} \frac{8^{2\sqrt{3}}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B8%5E%7B2%5Csqrt%7B3%7D%7D%7D%7B4%7D)
P=16√3(cm²)
c)
2.![\frac{3a^{2}\sqrt{3}}{2} \frac{3a^{2}\sqrt{3}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3a%5E%7B2%7D%5Csqrt%7B3%7D%7D%7B2%7D)