Question

Majac dane wielomiany H(x)=3x do potegi 3 + 2x do potegi 2x-1 i K(x)=4x do potegi drugiej+ 4x wyznacz wielomiany H(x)-5K(x)

Answer 1

H(x) = 3x^3 +2x^2 + x -1
K(x) = 4x^2 + 4x

H(x) - K(x) = 3x^3 + 2x^2 + x -1 - 5*(4x^2 + 4x) = 3x^3 +2x^2 + x -1 - 20x^2 - 20x = 3x^3 - 18x^2 - 19x -1