Question

Berapa tekanan yang dialami penyelam yang berada pada posisi 100 m diatas dasar laut? (kedalaman laut = 1 km. massa jenis air laut : 1,025×10^3 kg/m^3)

Answer 1

H = 1 km -100 m
= 1000 -100 = 900 m
p=(1,025 x 10^3) kg/m^3=1025 kg/m^3
g = 10 m/s^2
Ph = ?
Penyelesaian:
Ph = pgh
= (1025)(10)(900)
= 9.225.000 N/m^2 = 9.225 kPa

Answer 2

Dik:
h₁ = 100m
h₂ = 1km = 1000m
ρ = 1,025 × 10³kg/m³ = 1025kg/m³
Dit:
P = ...?
Jawab:
P = ρ g h
P = 1025 . 10 . (1000 - 100)
P = 10250 . 900
P = 9.225.000N/m²