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ΔTf = 3,37
kf= 1,86
molalitas = 1 molal
KI merupakan larutan elektrolit maka
KI→ K⁺ + I⁻
n= 2
i = 1 + (n-1)α
i = 1 + (2-1)α
i = 1 + α
ΔTf = m x Kf x i
3,37 = 1 x 1,86 x (1 + α )
3,37/1,86 = 1 +α
1,81 = 1 +α
α = 1,81 - 1
α = 0,81
jadi, derajat ionisasinya 0,81 =)