Question

Luas daerah antara kurva y = x3 - x2 - 6x da sumbu x adalah

Answer 1

Y = x^3 - x^2 - 6x
x = 0--> y = 0
y = 0 --> x (x^2 -x - 6)= 0
x(x-3)(x+2)= 0 --> x= -2 , x = 0 , x= 3

L =₋₂⁰ ∫x^3 - x^2 - 6x dx - ₀³∫ x^3 - x^2 - 6x dx 
L = 1/4 x^4 - 1/3 x^3 - 3x^2 ]⁰₋₂ - [1/4x^4 -1/3x^3 -3x^2]³₀
L = 1/4(-16) - 1/3(8) -3(-4) - [1/4(81)  - 1/3(27) - 3(9)]
L = -4 - 8/3 + 12 - 81/4 + 9 + 27
L = 29 ¹/₁₂