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W drugim podobnie, Ponieważ więc tu ze wzoru otrzymam
log_10 10=1
log_10 100=2 bo 10^2=100
log3 +log100=log(3*100)=log300
3-log_2 5=log_2 8-log _2 5=log_2(8:5)=log_2 8/5
log_2 8=3 bo 2^3=8