logarytmy do rozwiązadia 4
log3 √3 = log3 3^(1/2) = 1/2 * log3 3 = 1/2 * 1 = 1/2
log√2/2 (8√2) = log√2/2 (2^3 * 2^(1/2)) = log2^(-1/2) 2^7/2 = log2^(-1/2) ([2^(-1/2)]^(-7) =
-7 * log2^(-1/2) ([2^(-1/2)] = -7 * 1 = -7
√2/2 = 2^(1/2) / 2^1 = 2^(-1/2)
log3 √9 = log3 3 = 1
log81 27 = log3^4 3^3 = log3^4 (3^4)^(3/4) = 3/4 * log3^4 3^4 = 3/4 * 1 = 3/4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
log3 √3 = log3 3^(1/2) = 1/2 * log3 3 = 1/2 * 1 = 1/2
log√2/2 (8√2) = log√2/2 (2^3 * 2^(1/2)) = log2^(-1/2) 2^7/2 = log2^(-1/2) ([2^(-1/2)]^(-7) =
-7 * log2^(-1/2) ([2^(-1/2)] = -7 * 1 = -7
√2/2 = 2^(1/2) / 2^1 = 2^(-1/2)
log3 √9 = log3 3 = 1
log81 27 = log3^4 3^3 = log3^4 (3^4)^(3/4) = 3/4 * log3^4 3^4 = 3/4 * 1 = 3/4