Question

logarytm przy podstawie 9 z 3 pierwiastków z 3.

dam naj!

Answer 1

log₉3√3=x

 

9^x=3√3

(3²)^x=3·3^½

3^(2x)=3^(1½)

2x=3/2   /:2

x=¾

Answer 2

lg9 3√3 = x

 

9^x = 3√3

(3²)^x = 3 * 3^(1/2)

3^2x = 3^(1  +1/2)

2x = 4/3

x = 3/2 * 1/2

x = 3/4