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³log 5 = m --> ^5 log 3 = (1/m)^7 log 5 = n --> ^5 log 7 = (1/n)
^35 log 15
= (^5 log 15) / (^5 log 35)
= (^5 log (5x3)) / (^5 log (5x7))
= (1 + ^5 log 3) / ( 1 + ^5 log 7)
= (1 + (1/m)) / (1 + (1/n))
= ( (m+1)/m) / ((n+1)/n)
= ( (m+1)(n+1)) /mn