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f(x) = (x + 2)/(3 - x)
y = (x + 2)/(3 - x)
3y - yx = x + 2
x + yx = 3y - 2
x( 1 + y) = 3y - 2
x = (3y - 2)/(y + 1)
Maka f-' (x) = (3x - 2)/(x + 1)
OPTION E
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f(x) = (2x + 1)/(x - 3)
y = (2x + 1)/(x - 3)
yx - 3y = 2x + 1
yx - 2x = 3y + 1
x(y - 2) = 3y + 1
x = (3y + 1) / (y - 2)
Maka f-'(x) = (3x + 1)/(x - 2)
OPTION B
#DONE