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Verified answer
^7 log 2 = a --> ²log 7 = 1/a²log 3 = b
^6 log 14
= (²log 14) / (²log 6)
= (²log (2x7)) / (²log (2x3))
= (²log 2 + ²log 7) / (²log 2+ ²log3)
= ( 1+ (1/a)) / (1 + b)
= ((a+1)/a) / (1+b)
= (a + 1) / (a(b+1))
jawab : c