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log5(2x-1)>log₅5
Mamy takie same podstawy więc porownujemy liczbe logarytmowana:
2x-1>5
2x>6 |:2
x>3
x∈(3;+∞)
zał. 2x-1>0
x>1/2
log₅(2x-1)>log₅5
2x-1>5
2x>6
x>3
x>1/2∧x>3→x∈(3,∞)