Jawab:
limit trigonometri bentuk 0/0
Penjelasan dengan langkah-langkah:
lim (4x - π --> 0 ) [ 1 - 2 sin x cos x ] / ( cos x - sin x )
.
4x- π = 0
x= π/4.
lim (x -> π/4 ) [ 1 - 2 sin x cos x ] / ( cos x - sin x ) bentuk tak tentu
= lim (x -> π/4 ) [ (cos x - sin x)²]/ ( cos x - sin x )
= lim (x -> π/4 ) cos x - sin x
= 0
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Jawab:
limit trigonometri bentuk 0/0
Penjelasan dengan langkah-langkah:
lim (4x - π --> 0 ) [ 1 - 2 sin x cos x ] / ( cos x - sin x )
.
4x- π = 0
x= π/4.
.
lim (x -> π/4 ) [ 1 - 2 sin x cos x ] / ( cos x - sin x ) bentuk tak tentu
= lim (x -> π/4 ) [ (cos x - sin x)²]/ ( cos x - sin x )
= lim (x -> π/4 ) cos x - sin x
= 0
.