Question

Lim (cos 4x-1) : (x tan 2x)
x-->0

Answer 1

 lim (x -> 0) : (cos 4x - 1)/(x tan 2x) 

= lim (x -> 0) : (1-2sin²(2x) - 1)/(x tan 2x) 

= lim (x -> 0) : (-2sin²(2x))/(x tan 2x) 

= lim (x -> 0) : (-2)(sin2x/tan2x)(sin2x/2x).2 

= (-2).1.1.2 

= -4