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(6x-5)-(3+x)=6x-5-3-x=5x-8 , czyli odp. c.)
2.)
[(k+7)+(2k-5)+(3k+1)]:3= [k+7+2k-5+3k+1]:3=[6k+3]:3=2k+1
3.)
a.) # ---> 4
b.) # ---> 3a