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Verified answer
Jawablimit
limit (√(9x-2) - √(9x+1))(√(9x-2) + √(9x+1)) /(√(9x-2) +√(9x+1))
x-> ∞
limit ( 9x-2 -(9x+1) / (√(9x-2) + √(9x+1))
x->∞
limit ( -3) / (√(9x-2) + √(9x+1))
x->∞
= (-3/x²) / √9 + √9)
= 0/6
= 0