Latwe zadanie:jesli wystepuje blad to bez texa: (6x-2y)^{2}-3(4x+3y)^{2}+5(6x-3y)^{2}-7x(x+\frac{3}{.... Question from @insaned

September 2018 2 15 Report

Latwe zadanie:

$(6x-2y)^{2}-3(4x+3y)^{2}+5(6x-3y)^{2}-7x(x+\frac{3}{7})$

jesli wystepuje blad to bez texa: (6x-2y)^{2}-3(4x+3y)^{2}+5(6x-3y)^{2}-7x(x+\frac{3}{7})

$\\(6x-2y)^{2}-3(4x+3y)^{2}+5(6x-3y)^{2}-7x(x+\frac{3}{7})=\\ 36x^2-24xy+4y^2-3(16x^2+24xy+9y^2)+5(36x^2-36xy+9y^2)-7x^2-3x=\\ 36x^2-24xy+4y^2-48x^2-72xy-27y^2+180x^2-180xy+45y^2-7x^2-3x=\\ 161x^2+22y^2-276xy-3x$

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basetla

(6x-2y)^-3(4x+3y)^+5(6x-3y)^-7x(x+3/7) =

=36x^-24xy+4y^-3(16x^+24xy+9y^)+5(36x^-36xy+9y^) -7x^-3x =

=36x^-24xy+4y^-48x^-72xy-27y^+180x^-180xy+45y^-7x^-3x =

=161x^ -276xy + 22y^ -3x

=======================

(^ - kwadrat)

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