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[H⁺] = 10⁻⁵
Rumus larutan penyangga :
[H⁺] = Ka • mol sisa asam/mol anion garam
10⁻⁵ = 10⁻⁵ • mol sisa asam/mol anion garam
mol sisa asam/mol anion garam = 10⁻⁵ / 10⁻⁵
mol sisa asam/mol anion garam = 1
mol sisa asam = mol anion garam
Persamaan reaksi :
CH₃COOH + NaOH → CH₃COONa + H₂O
a 2x mol x mol
r x mol x mol
____________________________________
s x mol – x mol
Jadi, mol CH₃COOH : NaOH = 2 : 1
Karena Molaritas kedua larutan sama, berarti Volume CH₃COOH : NaOH = 2 : 1
Sehingga, volume masing-masingnya bisa banyak kemungkinan. Misalnya Volume CH₃COOH = 100 mL, sementara volume NaOH = 50 mL.
Mungkin ini soal pilihan ganda, tapi gak ditulis optionnya