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f(x)
= Int f'(x) dx
= Int 5 cos x + 4 sin x dx
Perlu diingat:
Int sin x dx = -cos x + C
Int cos x dx = sin x + C
Sehingga menjadi:
= Int 5 cos x dx + Int 4 sin x dx
= 5. Int cos x dx + 4. Int sin x dx
= 5.sin x + 4(-cos x) + C
= 5sin x - 4cos x + C
Dengan f(π/2) = 3
3 = 5sin π/2 - 4cos π/2 + C
3 = 5(1) - 4(0) + C
3 = 5 - 0 + C
3 = 5 + C
C = -2
Sehingga:
f(x) = 5 sin x - 4 cos x - 2