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x, x+1 y x+2.
La suma entre los tres lados da 120:
x + (x+1)+(x+2)=120;
x+ x + x + 1 + 2 = 120; 3x+ 3 = 120; x= (120-3)/3; x= 39;
Por lo tanto los lados del triángulo son:
39, 40 y 41.