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3a = 4b ec. 2
De la ec. 2:
a = 4b/3 ec. 3
Sustituyendo valores de al ec. 3 en al ec. 1:
3.5² = (4b/3)² + b²
12.25 = 16/9 b² + b²
12.25 = 16/9 b² + 9/9 b²
12.25 = 25/9 b²
12 1/4 = 25/9 b²
48/4 + 1/4 = 25/9 b²
49/4 = 25/9 b²
b² = (49*4) / (25/9)
b² = (49*9) / (4*25)
b² = 441/100
b² = 4.41
b = √4.41
b = 2.1
De la ec. 2:
3a = 4b
3a = 4*2.1
3a = 8.4
a = 8.4/3
a = 2.8
El perímetro entonces es:
P = 2*(2.8 + 2.1)
P = 2*4.9
P = 9.8
El perímetro es de:
9.8 metros
Saludos..............