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pKso = 10
Kso = 10^(-pKso) = 10⁻¹⁰
BaCl₂ :
V = 50ml
C = 0,0001 mol/l
0,0001 mola --------- 1000ml
x mola ------------------ 50ml
x = 5*10⁻⁶ mola
H₂SO₄:
V = 0,5ml
C = 0,0001 mol/l
0,0001 mola --------- 1000ml
x mola ------------------ 0,5ml
x = 5*10⁻⁸ mola
[Ba²⁺] :
5*10⁻⁶ mola -------- 50,5 ml
x mola --------------- 1000ml
x = 9,90*10⁻⁵ mol/l
[SO₄²⁻]:
5*10⁻⁸ mola -------- 50,5 ml
x mola --------------- 1000ml
x = 9,90*10⁻⁷ mol/l
Kso wyliczone= [Ba²⁺]*[SO₄²⁻]
Kso wyliczone= (9,90*10⁻⁵) * (9,90*10⁻⁷)
Kso wyliczone= 9,801*10⁻¹¹
Kso wyliczone = 9,801*10⁻¹¹
Kso = 10⁻¹⁰
Kso wyliczone < Kso
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