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GRAFIK FUNGSIGrafik fungsi bernilai minimum saat f'(x) = 0
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Titik minimum dpt ditentukan dgn turunanf'(x) = -1/2 (25-x^2)^-1/2 (-2x) = 0
Diperoleh x = 0.
Substitusikan x = 0 ke pers semula
f(0) = 7 - akar (25-0) = 7 - 5 =2.
Jadi a = 0 dan b = 2 sehingga
a^2 + b^2 = 4.