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Verified answer
N CO2 = 264 / 44 = 6 moln H2O = 54 / 18 = 3 mol
CxHy + O2 -> 6CO2 + 3H2O
Rumus molekul : C6H6 (Benzena) (D) -> Jawab
Verified answer
CxHy+O2>CO2+H2O264/44 mol. 54/18 mol
6 mol: 3 mol
CxHy=C6H6
Jawaban=D)C6H6